A 100g cube of ice at 0C is dropped into 1.0kg of water thatwas originally at 80C. What is the final temperature of thewater after the ice has melted?&nbsp;Q=±mL?&nbsp;or ?Qk=0 ???and ifso, how?

Question

A 100g cube of ice at 0C is dropped into 1.0kg of water thatwas originally at 80C. What is the final temperature of thewater after the ice has melted?&amp;nbsp;Q=±mL?&amp;nbsp;or ?Qk=0 ???and ifso, how?

Elberte · Accepted Answer

Here in this problem there are three stages.    One is the energy required to melt ice.    Second one to rise the temperature of melted ice from0  0  C to the final temperatureT  f  .    And third one is the energy lost by the water to from thetemperature 80  0  C to the finaltemperature(T  f  ).  Now according to the law of conservation of energy the amountof heat taken is equal to the amoount of heat lost.    So  miceLf+miceCwater(Tf−00C)=mwaterCwater(800−Tf)    Here c water = 4186J/kg.  0    C    L    f=3.33×105  J/kg  And m  ice  = 100g = 0.1kg    mwater =1.0kg    Now substitute all the given values in the above mentionedformula and then solve for the value of the finaltemperature(Tf).

A 100g cube of ice at 0C is dropped into 1.0kg of water thatwas originally at 80C. What is the final temperature of thewater after the ice has melted? Q=\pm mL ? or ?Qk=0 ???and ifso, how?

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