A 62.1kg mal ice skater is facing a 42.8kg female ice skater. they are at rest on theice they push off each other and move in opposite directions. The female skatermoves backwards with a speed of 3.11 m/s. determine the post-impulse speed of the male skater.

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Coraducci0d · Accepted Answer

mass of male ice skater      m    1    =  62.1  k  gmass of female ice skater      m    2    =  42.0  k  gInitially both are at rest i.e      u    1    =      u    2    =  0Initial, linear mo.      p    i    =      m    1        u    1    +      m    2        u    2    =  0  +  0        p    i    =  0Now, they starts moving in opposite direction and speeds are belowspeed of female ice skates      v    2    =  3.11  m      /    s  e  c (opposite to male skates)let the speed of male ice skaterFinal, total linear mo.      ρ    f    =      m    1        v    1    +      m    2        v    2      =  62.1  ×  v  +  42.0  (  −  3.11  )      ρ    f    =  62.1  v  −  133.11From conservation of linear momentum      ρ    i    =      ρ    f    0  =  62.1  v  −  133.11    62.1  v  =  133.11    v  =  2.14  m      /    s  e  cHence, the speed of male ice skater will be 2.14m/sec

A 62.1kg mal ice skater is facing a 42.8kg female ice skater. they are at rest on the ice they push off each other and move in opposite directions. The female skater moves backwards with a speed of 3.11 m/s. determine the post-impulse speed of the male skater.

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