Assuming all bulbs are identical, rank the brightness of the bulbs, from brightest to dimmest. A) all have equal brightness; B) A > B=C > D=H > E=F=G; C)A > D=H > E=F=G > B=C; D)A > D=H > B=C > E=F=G

ImmonoKedo8bj

ImmonoKedo8bj

Answered question

2023-02-25

Assuming all bulbs are identical, rank the brightness of the bulbs, from brightest to dimmest.
A) all have equal brightness
B) A > B=C > D=H > E=F=G
C)A > D=H > E=F=G > B=C
D)A > D=H > B=C > E=F=G

Answer & Explanation

Jamarion Turner

Jamarion Turner

Beginner2023-02-26Added 3 answers

The right answer is (D) A > D=H > B=C > E=F=G
Brightness of the bulb current through the bulb
Let R represent the resistance of each bulb
Regarding the branch containing bulbs A, B, and C
R e q = R + [ R × R R + R ] = R + R 2 = 3 R 2 i = 2 E 3 R
Current through A = 2 E 3 R
Current through B and C A = 1 2 [ 2 E 3 R ] = E 3 R
For the branch containing D,E,F,G and H
R e q = R + R 3 + R = 7 R 3 i = 3 E 7 R
Current through D and H = 3 E 7 R
Current through E,F,G = 1 3 ( 3 E 7 R ) = E 7 R
Hence the bulbs from brightest to dimmest can be arranged as
A > D=H > B=C > E=F=G
Hence, option (a) is correct.

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