rheisf

2021-12-27

Follow these guided instructions to solve the worded problem below.
a) Assign a variable (name your variable)
b) write expression/s using your assigned variable,
c) formulate your algebraic inequality
d) Solve the algebraic inequality
Worded Inequality problem: Your math test scores are 68, 78, 90 and 91. What is the lowest score you can earn on the next test and still achieve an average of at least 85?

### Answer & Explanation

kalfswors0m

Given: Math test scores are 68,78,90 and 91.
To find: The next lowest score on the next test and still achieve an average of at least 85.
Solution:
Average marks is given by formula:
$Average=\frac{\text{sum of marks in test}}{\text{number of test}}$
Let marks scored in next be x.
Total number of test including next will be 5.
Therefore,
$Average=\frac{\text{sum of marks in test}}{\text{number of test}}$
$85=\frac{68+78+90+91+x}{5}$
$85×5=327+x$
$425=327+x$
$x=425-327$
$x=98$
Hence, least marks required to achieve average marks of 85 is 98.

Gerald Lopez

a) Let us assume that the lowest score I can earn is x on the next test and still achieve an average of at least 85.
b) So my average score is $=\frac{68+78+90+91+x}{5}=\frac{327+x}{5}$
c) Given that my average score is at least 85.
so, $\frac{327+x}{5}\ge 85$
d) Then we solve the inequality
$\frac{327+x}{5}\ge 85$
$327+x\ge 5\left(85\right)$
$327+x\ge 425$
$x\ge 425-327$
$x\ge 98$
e) The lowest score I can earn is 98 on the next test and still achieve an average of at least 85.

karton

a) Let us assume that the lowest score I can earn is x on the next test and still achieve an average of at least 85.
b) So my average score is $=\frac{68+78+90+91+x}{5}=\frac{327+x}{5}$
c) so, $\frac{327+x}{5}\ge 85$
d) $\frac{327+x}{5}\ge 85$
$327+x\ge 5\left(85\right)$
$327+x\ge 425$
$x\ge 425-327$
$x\ge 98$
e) The lowest score I can earn is 98 on the next test and still achieve an average of at least 85.

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