How do you graph y=−x2−8x−13?

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suzzzlesv7 · Accepted Answer

Step 1&amp;nbsp;Think about your equation&#039;s general form, which is as follows:y=ax2+bx+c&amp;nbsp;in your case:&amp;nbsp;a=−1&amp;nbsp;b=−8&amp;nbsp;c=−13&amp;nbsp;In light of this, you can begin:You should take into account a number of fascinating factors before you plot your graphStep 2&amp;nbsp;The vertex: this is the lowest point reached by your parabola.&amp;nbsp;The coordinates of this point are given by:&amp;nbsp;xv=−b2a&amp;nbsp;and&amp;nbsp;yv=−Δ4a&amp;nbsp;Where&amp;nbsp;Δ=b2−4ac&amp;nbsp;giving:&amp;nbsp;xv=−4&amp;nbsp;and&amp;nbsp;yv=3&amp;nbsp;Step 3&amp;nbsp;The y-axis intercept:&amp;nbsp;Obtained setting&amp;nbsp;x=0&amp;nbsp;Giving:&amp;nbsp;x=0&amp;nbsp;and&amp;nbsp;y=−13&amp;nbsp;Step 4&amp;nbsp;The x-axis intercept(s):&amp;nbsp;obtained setting&amp;nbsp;y=0&amp;nbsp;and solving the corresponding second degree equation:&amp;nbsp;i.e.:&amp;nbsp;−x2−8x−13=0&amp;nbsp;Giving:&amp;nbsp;x1=−5.7&amp;nbsp;and&amp;nbsp;x2=−2.3&amp;nbsp;Your Parabola has&amp;nbsp;a&amp;lt;0&amp;nbsp;so that is downward oriented.&amp;nbsp;Finally:&amp;nbsp;Graph:&amp;nbsp;{−x2−8x−13[−10,&amp;nbsp;10,&amp;nbsp;−5,&amp;nbsp;5]}

How do you graph y=-x^{2}-8x-13?

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