How do you solve 6h2+17h+12=0?

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How do you solve  6h2+17h+12=0?

cevarnamvu · Accepted Answer

Step 1  6h2+17h+12=0  We can Split the Middle Term of this equation to factorise it and then find the solution for the equation  In this technique, if we have to factorise an expression like ah2+bh+c, e need to think of 2 numbers such that:  N1×N2=a×c=6×12=72  and N1+N2=b=17  After trying out a few numbers we get N1=9 and N2=8  9×8=72, and 9+8=17  6h2+17h+12=6h2+9h+8h+12  =3h(2h+3)+4(2h+3)  =(3h+4)(2h+3)  the solution for the equation is:  h=−43  h=−32

Darian Sosa · Accepted Answer

Step 1  Solve: 6h2+17h+12=0  Multiply 6 time 12 to get 72  Find two numbers that when multiplied equal 72 and when added equal 17  Numbers 8 and 9 mett the criteria  Write the equation substituting 8h and 9h for 17h  6h2+8h+9h+12=0  Separate the first two terms from the second two terms.  (6h2+8h)+(9h+12)  Factor out the GCF from both sets of terms.  2h(3h+4)+3(3h+4)=0  Factor out the GCF (3h+4)  (3h+4)(2h+3)=0  Solve for h.  3h+4=0  3h=−4  h=−43  2h+3=0  2h=−3  h=−32  h=−32, −43

How do you solve 6h^{2}+17h+12=0?

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