The complex zeros of f 1x2 = x4 + 1

Motalli21

Motalli21

Answered question

2022-01-29

The complex zeros of f 1x2 = x4 + 1 For the function f1x2 = x4 + 1:
(a) Factor f into the product of two irreducible quadratics. (Hint: Complete the square by adding and
subtracting 2x2
.2
(b) Find the zeros of f by finding the zeros of each irreducible quadratic.

Answer & Explanation

pripravyf

pripravyf

Beginner2022-01-30Added 12 answers

Step 1 Given : f(x)=x4+1 f(x)=x4+2x2+12x2(Add and subtract 2x2) =(x2+1)22x)2 f(x)=(x2+1+2x)(x2+12x (usingα2b2+(a+b)(ab))
Tapanuiwp

Tapanuiwp

Beginner2022-01-31Added 13 answers

b) To find the zeros of f:
We find the zeroes of x2+1+2x=0andx2+12x=0
Using quadratic formula,
x=b±b24ac2a
x=2±(22)4(1)(1)2(1),(2)±(22)4(1)(1)2(1)
x=2±242,2±242
x=2±i22,2±i22
Hence, there are no real zeroes. And the complex zeroes of f(x)=x4=1
are
x=2±i22andx=2±i22

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?