Proving that x^2-2xy+6y^2-12x+2y+41\ge 0 where x, y \in \mathbb{R}

amevaa0y

amevaa0y

Answered question

2022-02-01

Proving that x22xy+6y212x+2y+410 where x, yR

Answer & Explanation

Troy Sutton

Troy Sutton

Beginner2022-02-02Added 13 answers

Let z=xy then
f(x,y)=z2+5y212z10y+41
=(z6)2+5(y1)2
Karly Logan

Karly Logan

Beginner2022-02-03Added 11 answers

In the original variables, your polynomial is (xy6)2+5(y1)2 and so is non-negative, equal to zero only when y=1 and then x=7, so (7, 1).
(100110611)(100050000)(116011001)=(1161616141)

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