Algebraic and Trigonometric expression is \(\displaystyle{>}{0}\) for

maxime99bl6

maxime99bl6

Answered question

2022-03-18

Algebraic and Trigonometric expression is >0 for all real x
2x2sinx+2xcosx+2x2+1

Answer & Explanation

eslasadadsc

eslasadadsc

Beginner2022-03-19Added 7 answers

Step 1
For sinx+1>0 we obtain:
2x2sinx+2xcosx+2x2+1=2(1+sin{x})x2+2xcos{x}+10
Because
Δ4=cos2x2(1+sin{x})=(1+sin{x})2<0.
If sin{x}+1=0 so
2x2sinx+2xcosx+2x2+1=1>0.
Keith Steele

Keith Steele

Beginner2022-03-20Added 2 answers

Step 1
By completing the square,
2(sinx+1)x2+2cosx,x+1
=2(sinx+1)(x+cosx2(sinx+1))2+1cos2x2(sinx+1)
=2(sinx+1)((x+cosx2(sinx+1))2+sinx+12)
Obviously, sinx+10. In case of equality, sinx=1cosx=0 and the expression reduces to 1.

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