At which values ​of the parameter k, there

Rubi Reid

Rubi Reid

Answered question

2022-03-16

At which values ​of the parameter k, there is no solution to the inequality
(k+1)x22kx+2k+2<0?

Answer & Explanation

Konnor Davidson

Konnor Davidson

Beginner2022-03-17Added 4 answers

Step 1
There seems some wrong points in your 'textbook solution' you posted, but I don't know if it is your typo or the textbook. Your solution is correct.
Using the textbook solution, we can achieve same result.
a=k+1, D=4[k22(k+1)2]
If k+1<0, we can be sure that for sufficiently large x, we always will have solution. we hence assume that k+10
{k+1>0k22(k+1)20{k>1k24k20k22
Hence solution is k[22, )

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