Let us consider some function \(\displaystyle{f{{\left({x},{y}\right)}}}:,{\mathbb{{R}}}^{{2}}\to{\mathbb{{R}}}\), such

ruililorNokmncf

ruililorNokmncf

Answered question

2022-03-22

Let us consider some function f(x,y):,R2R, such that
f(x,y)x=a,x+b,yf(x,y)y=b,x+c,yf(0,0)=0
where a, b, cR.

Answer & Explanation

Jambrichp2w2

Jambrichp2w2

Beginner2022-03-23Added 12 answers

You've gotten the formula for computing f(x,y) wrong; you need to set y to be 0 in your integral using dx'.
The reason for this is that you're finding f(x,y) by integrating along two paths; first from (0,0) to (x,0), and then from (x,0) to (x,y). The first path has y=0 at all times.

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