What is the number of length-7 sequences from the numerical

hornejada1c

hornejada1c

Answered question

2022-06-29

What is the number of length-7 sequences from the numerical digits {0,1,2,3,4,5,6,7,8,9} such that the sequence uses exactly 4 different digits?

Answer & Explanation

Keely Fernandez

Keely Fernandez

Beginner2022-06-30Added 14 answers

1) Choose exactly 4 different digits from the list of 10 digits.
2) Arrange above 4 different digits at 7 places such that the created sequence consists of exactly 4 different digits.
Find the number of ways for doing the first point.
From the selection or combination rule it will be 10 C 4 .. Evaluate 10 C 4 . using the formula n C r = n ! r ! ( n r ) !
10 C 4 = 10 ! 4 ! ( 10 4 ) !
= 10 ! 4 ! × 6 !
= 10 × 9 × 8 × 7 × 6 ! 24 × 6 !
= 10 × 9 × 8 24 × 7
= 10 × 3 × 7
= 210
Thus, the first event done in 210 ways
Now, find the number of ways for doing a second event. Use the above four numbers to create a length-7 sequence without any condition.
Thus, way each digit has 4 choices therefore the total number of such sequences is 47.
We have to make a sequence which consists of exactly 4 different digits. Remove the sequences from a set which has only 3 different digits or less than it.
Find the number of sequences which consist of 3 different digits or less than it from the selected 4 different digits. Then choose any three digits from 4 different digits by 4 C 3 ways. Each position has 3 choices and there are 7 such positions so numbers of choices is 37.
Therefore, such sequences are 4 C 3 × 3 7 .
Subtract 4 C 3 × 3 7 from 4 7 to get the number of sequences which consist of exactly 4 different digits which are selected in the first step.
4 7 4 C 3 × 3 7 = 16384 4 ( 2187 )
= 16384 8748
= 7636
Thus, the second event done in 7636 ways
Use the fundamental principle of counting to find required the number of length-7 sequences. Since number of ways of occurring first event is 210 ways and second event is 7636 ways so required number is = 210 × 7636
= 1603560

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