Find f^(-1) and verify that (fxf^(-1))(x)=(f^(-1)xf)(x)=x da x in betwwen da*f* is muliply 1.)f(x)=x^3-1 da answer is f^(-1)(x)=(x+1)^(1/3) or root(3)(x+1) da 1/3 is an exponent please explain in detail how to get daanswer

abrigairaic

abrigairaic

Answered question

2022-08-08

Find f 1 and verify that
( f x f 1 ) ( x ) = ( f 1 x f ) ( x ) = x da x in betwwen da*f* is muliply
1.) f ( x ) = x 3 1
da answer is f 1 ( x ) = ( x + 1 ) 1 / 3 or x + 1 3 da
1/3 is an exponent please explain in detail how to get da answer

Answer & Explanation

kunstdansvo

kunstdansvo

Beginner2022-08-09Added 16 answers

To find the inverse of of f(x)
Recall that f(x) = y. The equation becomes y = x 3 1
To begin switch the y with the x and switch the x with the y(in other words the x and y switch). The equation is now:
x = y 3 1
Now, solve for y
y 3 = x + 1 (derived by isolating t h e y 3 )
y 3 3 = x + 1 3 To solve for y, we need to get rid of theexponent. Since its cubed, we cube root it. But what you do to oneside, you have to do to the other side, so we also must cube rootthe x+1
y = x + 1 3
y = ( x + 1 ) 1 3 exponent 1/3 meanscube root. The denominator of a fraction exponent denotes the root,the numerator of the fraction exponent denotes the exponent. x m n = x m n
Now write it using inverse notation:
f 1 ( x ) = x + 1 3
Trystan Castaneda

Trystan Castaneda

Beginner2022-08-10Added 5 answers

Find f 1 ( x ) for f ( x ) = x 3 1
To find f 1 ( x ) :
1. Replace f(x) with y.
2. Interchange x and y. (This gives the inverse function.)
3. Solve for y.
4. Replace y with f 1 ( x ). (This is inverse function notation.)
1. y = x 3 1
2. x = y 3 1
3. x + 1 = y 3
x + 1 3 = y cube root each side to solve for y.Also, y 3 3 = ( y 3 ) 1 / 3 = y
4. f 1 ( x ) = x + 1 3
Prove that ( f f 1 ) ( x ) = f ( f 1 ( x ) ) = x
f ( x + 1 3 ) = ( x + 1 3 ) 3 1 = ( x + 1 ) 1 = x + 1 1 = x
So it does = x.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?