Consider the following statements:- f(x)=1/(1-IxI) is (i) a real valued one to one function from (0,1) onto (1, infty) (ii)a real valued funcion ,one to one function from (-infty , infty) onto (-infty, infty) (ii) (iii) a real valued one to one funtionti on from (-infty , -1) onto (-infty , 0) Which of the statements given above are correct?

Pranav Ward

Pranav Ward

Answered question

2022-09-02

Consider the following statements:-
f(x)=1/(1-IxI) is
(i) a real valued one to one function from (0,1) onto ( 1 , )
(ii)a real valued funcion ,one to one function from ( , ) onto ( , )(ii)
(iii) a real valued one to one funtionti on from ( , 1 ) onto ( , 0 )
Which of the statements given above are correct?

Answer & Explanation

lilhova13b3

lilhova13b3

Beginner2022-09-03Added 12 answers

f(x)=1/(1-IxI)
The domain of x is all reals except 1, -1
As x goes from 0 to 1, ygoes from 1 to .
As x goes from 1 to y goes from to 0.
And all that is mirrored on the left side of the graph.
drobtinicnu

drobtinicnu

Beginner2022-09-04Added 4 answers

I would say that (i) and (iii) are correct. (ii) is not correct because the domain of the function does not include -1 and 1 while the domain in (ii) does include these two numbers. However, as the person above me stated as x goes (0, 1) then y goes ( 1 , ). As x goes ( 1 , ) y goes ( , 0 ); since this is an absolute value function the same is true for x ( , 1 ) y goes ( 1 , ).

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?