A smart-phone is thrown upwards from the top of a 192-foot building with an initial velocity of 16 feet per second. The height h of the smart-phone after t seconds is given by the quadratic equation h = − 16 t 2 + 16 t + 192 h. When will the smart-phone hit the ground?

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A smart-phone is thrown upwards from the top of a 192-foot building with an initial velocity of 16 feet per second. The height h of the smart-phone after t seconds is given by the quadratic equation   h  =  −  16      t    2    +  16  t  +  192  h. When will the smart-phone hit the ground?

Karma Estes · Accepted Answer

Answer:  h  =  −  16      t    2    +  16  t  +  192  hWhen it hits the ground h=0  0  =  −  16      t    2    +  16  t  +  192    16      t    2    −  16  t  −  192  =  0    16  (      t    2    −  t  −  12  )  =  0        t    2    −  t  −  12  =  0        t    2    +  4  t  −  3  t  −  12  =  0    t  (  t  +  4  )  −  3  (  t  +  4  )  =  0    (  t  −  3  )  (  t  +  4  )  =  0    t  =  3    t  =  −  4At t=3, it wel hit the group

A smart-phone is thrown upwards from the top of a 192-foot building with an initial velocity of 16 feet per second. The height h of the smart-phone after t seconds is given by the quadratic equation h=−16t^2+16t+192h. When will the smart-phone hit the ground?

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