treallt5

2022-09-14

Find the slope perpendicular to 5x+2y=10

Mohammed Farley

Beginner2022-09-15Added 15 answers

Given -

$5x+2y=10$

Slope of the given line is $m}_{1}=-\frac{a}{b}=-\frac{5}{2$

Two lines are perpendicular when ${m}_{1}\times {m}_{2}=-1$

Then

$m}_{2}=-\frac{1}{{m}_{1}}=-1\xf7-\frac{5}{2}=-1\times -\frac{2}{5}=\frac{2}{5$

$m}_{2}=\frac{2}{5$

$5x+2y=10$

Slope of the given line is $m}_{1}=-\frac{a}{b}=-\frac{5}{2$

Two lines are perpendicular when ${m}_{1}\times {m}_{2}=-1$

Then

$m}_{2}=-\frac{1}{{m}_{1}}=-1\xf7-\frac{5}{2}=-1\times -\frac{2}{5}=\frac{2}{5$

$m}_{2}=\frac{2}{5$

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