Mr. and Mrs. Ahuja weigh π‘₯ kg and 𝑦 kg respectively. They both take a dieting course at the end of which Mr. Ahuja loses 5 kg and weighs as much as the wife weighed before the course. Mrs. Ahuja loses 4 kg and weighs 7/8th of what her husband weighed before the course. From two equations in π‘₯ and 𝑦 and hence find their present weights.

hommequidort0h

hommequidort0h

Answered question

2022-09-23

Mr. and Mrs. Ahuja weigh π‘₯ kg and 𝑦 kg respectively. They both take a dieting course at the end of which Mr. Ahuja loses 5 kg and weighs as much as the wife weighed before the course. Mrs. Ahuja loses 4 kg and weighs 7/8th of what her husband weighed before the course. From two equations in π‘₯ and 𝑦 and hence find their present weights.

Answer & Explanation

anekesanxl

anekesanxl

Beginner2022-09-24Added 12 answers

y = x βˆ’ 5 and y βˆ’ 4 = 7 8 x ⟹ y βˆ’ 4 = ( x βˆ’ 5 ) ⏟ y βˆ’ 4 = 7 8 x
Multiplying both sides of the equation by Multiplying both sides of the equation by 8 gives us gives us
8 ( x βˆ’ 5 ) βˆ’ 8 β‹… 4 = 7 x ⟺ 8 x βˆ’ 72 βˆ’ 7 x = 0 ⟺ x = 72 Β kg .
Now solve for y = x βˆ’ 5 = 72 βˆ’ 5 = 67 Β kg
Recall that x , y give the weights prior to losing weight. So we need to find current weights: Mr: x βˆ’ 5 = 72 βˆ’ 5 = 67, Mrs: 67 βˆ’ 4 = 63.
Liberty Page

Liberty Page

Beginner2022-09-25Added 3 answers

y = x βˆ’ 5
y = 7 8 x + 4
Set them equal to each other, solve for x. Then substitute x into one of the original equations to find y.
Should find that x = 72 kg and y = 67 kg.

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