Summer and Jason's present ages add up to 107 years. If 11 years ago Jason's age was four times Summer's age, how old is Jason now?

Cortez Clarke

Cortez Clarke

Answered question

2022-11-05

Summer and Jason's present ages add up to 107 years. If 11 years ago Jason's age was four times Summer's age, how old is Jason now?

Answer & Explanation

Calvin Maddox

Calvin Maddox

Beginner2022-11-06Added 15 answers

Let the Summer's age, 11 years ago, be x years. As 11 years ago Jason's age was four times Summer's age, Jason's age 11 years ago would have been 4x years.
Hence, their present ages are x+11 and 4x+11 and as sum of their ages now is 107 years, we have
x+11+4x+11=107
or 5x=107−11−11=85
i.e. x = 85 5 = 17
Hence, 11 years ago, Summer and Jason were 17 and 17 × 4 = 68 years respectively.
and Jason is 68+11=79 years old now.

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