Nonlinear system: (y_1y_2)=(2y_1 y^2_1) Giving the jacobian of transformation being: F=(2 0, 2y_1 0)=(0 0, 2 0)(F_1 F_2)+(2 0)

Siemensueqw

Siemensueqw

Answered question

2022-11-10

Nonlinear system:
( y ˙ 1 y ˙ 2 ) = ( 2 y 1 y 1 2 )
Giving the jacobian of transformation being:
F ˙ = ( 2 0 2 y 1 0 ) = ( 0 0 2 0 ) ( F 1 F 2 ) + ( 2 0 )
Which gives me the eigenvalues λ = 0 2 = 0 , 0 meaning a degenerate node since we have only the eigenvector:
F ( 1 ) = ( 0 1 )
Non-linear system with all trajectories converging on the line x = 0, rather than ( 2 , 0 )?

Answer & Explanation

iletsa2ym

iletsa2ym

Beginner2022-11-11Added 22 answers

( y ˙ 1 y ˙ 2 ) = ( 2 y 1 y 1 2 )
We want the critical points of this system, which we can find by taking:
( 0 0 ) = ( 2 y 1 y 1 2 )
( 0 , α ) are the spots of the critical points, thus there are infinite critical points at x = 0
Rosemary Chase

Rosemary Chase

Beginner2022-11-12Added 4 answers

You have made a mistake in your Jacobian.
Since we are taking F = y ˙ , we need to be very clear that this means:
( F 1 F 2 ) = ( 2 y 1 y 1 2 )
And hence: F ˙ = ( F ˙ 1 F ˙ 2 ) = ( 2 0 2 y 1 0 ) = ( 0 0 1 0 ) ( F 1 F 2 ) + ( 2 0 )

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