illusiia

2021-08-12

A party mix is a mixture of nuts that are sold for $2.50 per kg to a cereal mixture that is sold for $1 per kg. How much of each needed to be added to obtain 60 kg of a mix that will be sold for $2.10 per kg?

Numbers of kilograms Price per kilogram(in dollars) Values(in dollars)

Nuts x 2.50

Cereal y 1.00

Mixture 2.10

Numbers of kilograms Price per kilogram(in dollars) Values(in dollars)

Nuts x 2.50

Cereal y 1.00

Mixture 2.10

Mitchel Aguirre

Skilled2021-08-13Added 94 answers

Let amount of nuts that sell for $2.50 per kg=x

amount of nuts that sell for $1 per kg=y

Total cost = cost of nuts of $2.50 per kg + cost of nuts of $1 per kg = 2.50x+y

Total amount of nuts = x+y

But resultant value of 1 kg nuts = 2.1

$\frac{2.5x+y}{x+y}=2.1$

$0.4x=1.1y$

$\frac{x}{y}=\frac{11}{4}$

$x=11k,y=4k$

total amount = 60

$x+y=60$

$11k+4k=60$

$15k=60$

$k=4$

Amount of nuts $2.50 per kg$=11k=11\cdot 4=44$

Amount of cereal $1 per kg$=4k=4\cdot 4=16$

The amount of nuts is 44 kg and cereal mixture is 16 kg to obtain 60 kg of a mix that will sell for $2.10 per kg

amount of nuts that sell for $1 per kg=y

Total cost = cost of nuts of $2.50 per kg + cost of nuts of $1 per kg = 2.50x+y

Total amount of nuts = x+y

But resultant value of 1 kg nuts = 2.1

total amount = 60

Amount of nuts $2.50 per kg

Amount of cereal $1 per kg

The amount of nuts is 44 kg and cereal mixture is 16 kg to obtain 60 kg of a mix that will sell for $2.10 per kg

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