illusiia

2021-08-12

A party mix is a mixture of nuts that are sold for $2.50 per kg to a cereal mixture that is sold for$1 per kg. How much of each needed to be added to obtain 60 kg of a mix that will be sold for $2.10 per kg? Numbers of kilograms Price per kilogram(in dollars) Values(in dollars) Nuts x 2.50 Cereal y 1.00 Mixture 2.10 ### Answer & Explanation Mitchel Aguirre Skilled2021-08-13Added 94 answers Let amount of nuts that sell for$2.50 per kg=x
amount of nuts that sell for $1 per kg=y Total cost = cost of nuts of$2.50 per kg + cost of nuts of $1 per kg = 2.50x+y Total amount of nuts = x+y But resultant value of 1 kg nuts = 2.1 $\frac{2.5x+y}{x+y}=2.1$ $0.4x=1.1y$ $\frac{x}{y}=\frac{11}{4}$ $x=11k,y=4k$ total amount = 60 $x+y=60$ $11k+4k=60$ $15k=60$ $k=4$ Amount of nuts$2.50 per kg $=11k=11\cdot 4=44$
Amount of cereal $1 per kg $=4k=4\cdot 4=16$ The amount of nuts is 44 kg and cereal mixture is 16 kg to obtain 60 kg of a mix that will sell for$2.10 per kg

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