Nann

2021-09-07

A city water department is proposing the construction of a new water pipe, as shown. The new pipe will be perpendicular to the old pipe. Write an equation that represents the new pipe.

Arham Warner

Skilled2021-09-08Added 102 answers

Calculation: As the line of existing water pipe is passes through the points (0,3) and (-3,-1).

Therefore slope of line is$\frac{-1-3}{-3-0}=\frac{-4}{-3}=\frac{4}{3}$ .

Let Slope of line of proposed water pipe is$={m}_{2}$ .

As the line of proposed water pipe is perpendicular to existing water pipe line.

${m}_{1}\cdot {m}_{2}=-1$

$\frac{4}{3}\cdot {m}_{2}=-1$

$m}_{2}=\frac{-3}{4$

Equation of proposed water pipe is:

$y-0=\frac{-3}{4}(x-2)$

$4y=-3x+6$

$3x+4y=6$

Thus Equation of proposed water pipe is$3x+4y=6$ .

Therefore slope of line is

Let Slope of line of proposed water pipe is

As the line of proposed water pipe is perpendicular to existing water pipe line.

Equation of proposed water pipe is:

Thus Equation of proposed water pipe is

2021-10-28

y−0=−34(x−2)
4y=−3x+6
3x+4y=6
y=-3/4x+1 1/2
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