A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. Ho

shadsiei

shadsiei

Answered question

2021-09-23

A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin returns to the juggler’s hand?

Answer & Explanation

yunitsiL

yunitsiL

Skilled2021-09-24Added 108 answers

The equation for a particle under constant acceleration also apply to the freely falling bodies.
The constant acceleration of the freely falling body is called the acceleration due to gravity, (ay=g=9.8 ms2)
Note: the starting point is the same as the ending point, so (yfyi=0)
To calculate the time, we will use the following equation:
yf=yi+vyit+12ayt2
yfyi=vyit+12ayt2
0=8.20t+12(9.8)t2
t=1.67 s
t=1.67 s

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