Using the root method, solve the following polynomial. 2x^{3}+16=0

interdicoxd

interdicoxd

Answered question

2021-12-12

Using the root method, solve the following polynomial.
2x3+16=0

Answer & Explanation

Chanell Sanborn

Chanell Sanborn

Beginner2021-12-13Added 41 answers

Step 1
Given that
2x3+16=0
2(x3+8)=0
(x3+8)=0
x3+23=0
Step 2
(x3+8)=0
x3+23=0
(x+2)(x22x+4)=0
x=2,x=2±4162
=2±23i2
x=1±3i
Hence, the roots are
2,13i & 1+3i

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