Lucille Davidson

2021-12-17

Solve.

$16{x}^{2}-25=0$

$x=B\otimes$

Jenny Sheppard

Beginner2021-12-18Added 35 answers

Step 1

Given Data:

Equation:$16{x}^{2}-25=0$

First, apply factorization in the given equation then solve for the values of x.

The useful factorization is,

$({a}^{2}-{b}^{2})=(a-b)(a+b)$

Step 2

Solve the given equation,

$16{x}^{2}-25=0$

${\left(4x\right)}^{2}-{\left(5\right)}^{2}=0$

(4x-5)(4x+5)=0

$x=\frac{5}{4}$ & $x=-\frac{5}{4}$

Thus, the values of x are$-\frac{5}{4}$ and $\frac{5}{4}$ (or -1.25 and 1.25).

Given Data:

Equation:

First, apply factorization in the given equation then solve for the values of x.

The useful factorization is,

Step 2

Solve the given equation,

(4x-5)(4x+5)=0

Thus, the values of x are

puhnut1m

Beginner2021-12-19Added 33 answers

We will first write the equation in standard form $a{x}^{2}+bx+c=0$ to identify a,b and c.

Where a is the coefficient of the$x}^{2$ term, b is the coefficient of the x term and c is the constant term.

Given equation:$16{x}^{2}-25=0$

The variable in the equation is x:$x=\frac{-b\pm \sqrt{{b}^{2}-4ac}}{2a}$

Use a=16, b=0 and c=-25:$x=\frac{-\left(0\right)\pm \sqrt{{\left(0\right)}^{2}-4\cdot 16\cdot (-25)}}{2\left(16\right)}$

$x=\frac{-0\pm \sqrt{0+1600}}{32}$

$x=\frac{\pm \sqrt{0+1600}}{32}$

Use$\sqrt{1600}=40:x=\frac{\pm 40}{32}$

We know$\frac{a\pm b}{c}$ means $\frac{a+b}{c}$ or $\frac{a-b}{c}:x=\frac{42}{30}$ or $x=-\frac{40}{32}$

Simplify:$x=\frac{5}{4}$ or $x=-\frac{5}{4}$

Hence the roots are$-\frac{5}{4}$ and $\frac{5}{4}$

Where a is the coefficient of the

Given equation:

The variable in the equation is x:

Use a=16, b=0 and c=-25:

Use

We know

Simplify:

Hence the roots are

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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