Cynthia Bell

2021-12-31

Solve the equation by factoring.

$2{x}^{2}-5x-3=0$

otoplilp1

Beginner2022-01-01Added 41 answers

Step 1

The given equation is,

$2{x}^{2}-5x-3=0$

The given equation can be solved using factorization.

Step 2

On solving the given equation, we get

$2{x}^{2}-5x-3=0$

$2{x}^{2}-6x+x-3=0$

2x(x-3)+1(x-3)=0

(2x+1)(x-3)=0

Hence,

2x+1=0

2x=-1

$x=-\frac{1}{2}$ ...(i)

And,

x-3=0

x=3...(ii)

Therefore, the solution of the given equation is -1/2 and 3.

The given equation is,

The given equation can be solved using factorization.

Step 2

On solving the given equation, we get

2x(x-3)+1(x-3)=0

(2x+1)(x-3)=0

Hence,

2x+1=0

2x=-1

And,

x-3=0

x=3...(ii)

Therefore, the solution of the given equation is -1/2 and 3.

levurdondishav4

Beginner2022-01-02Added 38 answers

In order to factor this you need to multiply -3 by 2 to get -6, the two factors of this problem will add to give you -5 and multiply to give you -6. once you have the factors you must divide the expression by 2.

next (2x-6)(2x+1)/2

pull out a 2 from (2x-6)

2(x-3)(2x+1)/2

the 2'scancel

and your solution is (x-3)(2x+1) the zeros are 3, -1/2

Vasquez

Expert2022-01-09Added 669 answers

1.Open up brackets:
()()
2.Break up the first term:
(2x)(x)
3.Break up the 3rd term such that the product of the x term and non x term given the middle number:
(2x+1)(x-3)

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