How do you write 6x^{2}-24x-5y^{2}-10y-11=0 in standard form?

Octavio Miller

Octavio Miller

Answered question

2022-01-29

How do you write 6x224x5y210y11=0 in standard form?

Answer & Explanation

Jude Carpenter

Jude Carpenter

Beginner2022-01-30Added 9 answers

The standard form of a hyperbola with a transverse axis (all stuff this is, trust me on this) is
(xh)2a2(yk)2b2=1
6x224x5y210y11=0
move he constant to the left side
6(x24x)5(y2+2y)=11
complete the squares
6(x24x+4)5(y2+2y+1)=11+245
6(x2)25(y+1)2=30
Divide by 30 so left side equals 1
(x2)2(5)2(y+1)2(6)2=1

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