How do you write in standard form y=4(x+5)-2(x+1)(x+1)?

Caleb Snyder

Caleb Snyder

Answered question

2022-01-29

How do you write in standard form y=4(x+5)-2(x+1)(x+1)?

Answer & Explanation

baltimi

baltimi

Beginner2022-01-30Added 7 answers

Explanation:
Since this expression has many parts, I will color-code it and tackle it one by one.
4(x+5)-2(x+1)(x+1)
For the expression in purple, all we need to do is distribute the 4 to both terms in the parenthesis. Doing this, we now have
4x+20-2(x+1)(x+1)
What I have in blue, we can multiply with the mnemonic FOIL, which stands for Firsts, Outsides, Insides, Lasts. This is the order we multiply the terms in.
Foiling (x+1)(x+1):
First terms: xx=x2
Outside terms: x*1=x
Inside terms: 1*x=x
Last terms: 1*1=1
This simplifies to x2+2x+1. We now have
4x+202(x2+2x+1)
Distributing the -2 to the blue terms gives us
4x+202x24x2
Combining like terms gives us
2x2+18
We see that our polynomial is in standard form, ax2+bx+c. Notice that the x terms cancel out, so we don't have a bx term.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?