What is the standard form of y-4=-(x-1)^{2}?

Connor Randall

Connor Randall

Answered question

2022-01-30

What is the standard form of y4=(x1)2?

Answer & Explanation

eris0cg

eris0cg

Beginner2022-01-31Added 13 answers

Explanation:
The standard form is
y=ax2+bx+c
(where a,b and c are some numbers)
So in this case, you just need to open up the parentheses of the right side of the equation and then rearrange the terms.
We have:
y4=(x1)2
which becomes:
y4=(x22x+1)
(note that I still keep the minus sign in front of the parenthesis)
y4=x2+2x1
And pass the -4 on the "other side":
y=x2+2x1+4
giving you:
y=x2+2x3
which is in standard form with
a=-1, b=2 and c=-3

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