What is the standard form of y=(-x+1)(-3x-2)(6x-1)?

Leroy Little

Leroy Little

Answered question

2022-01-31

What is the standard form of y=(-x+1)(-3x-2)(6x-1)?

Answer & Explanation

ribejat1f3

ribejat1f3

Beginner2022-02-01Added 8 answers

Explanation:
The given seems like the factored form
y=(-x+1)(-3x-2)(6x-1)
For what I know, standard form is that kind of arrangement of the terms from highest degree to the lowest degree term after multiplying all these factors.
y=(-x+1)(-3x-2)(6x-1)
multiply the first two factors
y=(3x2+2x3x2)(6x1)
simplify by combining similar terms
y=(3x2x2)(6x1)
multiply the remaining factors
y=18x36x212x3x2+x+2
simplify again to obtain the final answer. Make sure the terms are arranged from highest to lowest degree
y=18x39x211x+2

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