What is the logaritmic form of v=Ae^(Bi) I am reading a scientific paper, which uses a model of the form v=Ae^(Bi) and then it says that this model has the following logarithmic form ln(v)=Bi+ln(A) where A is a constant. But the right logarithmic form of the equation above isn't ln(v)=Bi+Bi∗ln(A) instead? I'm I doing somehting wrong?

kalkulusk2

kalkulusk2

Open question

2022-08-19

What is the logaritmic form of v = A e B i
I am reading a scientific paper, which uses a model of the form v = A e B i and then it says that this model has the following logarithmic form
ln ( v ) = B i + l n ( A ) where A is a constant. But the right logarithmic form of the equation above isn't ln ( v ) = B i + B i l n ( A ) instead?
I'm I doing somehting wrong?

Answer & Explanation

Charlee Beck

Charlee Beck

Beginner2022-08-20Added 6 answers

Work out the steps:
v = A e B i
ln ( v ) = ln ( A e B i )
ln ( v ) = ln ( A ) + ln ( e B i )
ln ( v ) = ln ( A ) + B i
You break over the multiplication inside the logarithm before you pull down the exponent. Because the B i is only an exponent on the e

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