Jo has 37 coins (all nickels, dimes and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?

reinzogoq

reinzogoq

Answered question

2022-09-04

Jo has 37 coins (all nickels, dimes and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?

Answer & Explanation

Mateo Tate

Mateo Tate

Beginner2022-09-05Added 18 answers

let x be the number of nickels
x+4 = number of quarters
37 - (x + x+4) = number of dimes
0.05x + 0.25(x+4) + 0.10(37 - 2x -4) = 5.50
0.05x +0.25x +1 +3.7 - 0.2x - 0.4 = 5.5
0.1x = 5.5 - 1 - 3.7 + 0.4 = 1.2
x = 12 nickels
x+4 = 16 quarters
37-12-16 = 9 dimes
inhiba5f

inhiba5f

Beginner2022-09-06Added 2 answers

let n = the number of nickels
4 + n = the number of quarters
37 - (4 + 2n) = the number of dimes
multiply by value of coin
.05n + .25(4+n)+.10(37-(4+2n))=5.50
5n+25(4+n)+10(33-2n)=550 multiply by 100 to eliminate decimals
5n+100+25n+330-20n=550 distributive property
10n+430=550 combine like terms
10n=120 inverse operations
n=12
12 nickels, 16 quarters, 9 dimes

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