Does loga/logb = log(a^(1/logb))? I know log(a^b)=blog(a). However, Wolfram Alpha tells me that (log(a))/(log(b)) does not equal log(a^(1)/(log(b))) Is Wolfram Alpha correct? If it is, why is it correct? I'm using base 10 logs instead of natural logs, although I doubt it makes a difference.
Marcelo Maxwell
Answered question
2022-09-19
Does loga/logb = log(a^(1/logb))? I know However, Wolfram Alpha tells me that does not equal Is Wolfram Alpha correct? If it is, why is it correct? I'm using base 10 logs instead of natural logs, although I doubt it makes a difference.
Answer & Explanation
moderrockblog09
Beginner2022-09-20Added 7 answers
Actually you are correct. However, you must take note that there are some constraints (which are pretty self-explanatory).
As long as,
Hope this helps you understand why. Comment if you have any questions.
mydaruma25
Beginner2022-09-21Added 2 answers
I think your issue might be that is a multivalued function if you allow complex outputs. This is due to the fact that for . The complex logarithm can give out different values as follows.
So when you take one value for the left hand side of your original equation, you could take a completely different one for the right hand side (though I'm not entirely certain that this is the reason).