Logorithms on a first level learning Solve log_(5x−1)4 = 1/3

Luisottifp

Luisottifp

Answered question

2022-09-20

Logorithms on a first level learning
Solve log 5 x 1   4 = 1 / 3
( 5 x 1 ) 1 / 3 =4
( ( 5 x 1 ) 1 / 3 ) 3 = 4 3
5 x 1 = 64
5 x = 65
13
I am not sure where to go with this. I learned some things about logs before my class ended for the year. I just wanted to expand on my knowledge. This is more advance than what I am use to doing. Can someone please show me.

Answer & Explanation

GrEettarim3

GrEettarim3

Beginner2022-09-21Added 6 answers

If I didn't understand all of the steps, I would try to include all steps. One step that is missing is explicitly raising the base to the power of the LHS and RHS respectively.
log 5 x 1 4 = 1 / 3
( 5 x 1 ) log 5 x 1 4 = ( 5 x 1 ) 1 / 3
We know that a log a Y = Y, similarly our equation becomes
4 = ( 5 x 1 ) 1 / 3
Now if 4 = ( 5 x 1 ) 1 / 3 then
4 4 4 = ( 5 x 1 ) 1 / 3 ( 5 x 1 ) 1 / 3 ( 5 x 1 ) 1 / 3
4 3 = ( 5 x 1 ) 1 / 3 + 1 / 3 + 1 / 3
64 = ( 5 x 1 ) 1 = 5 x 1
deiluefniwf

deiluefniwf

Beginner2022-09-22Added 4 answers

It is easier if after the second line you cube both sides.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?