Why does int_a^(ab)1/xdx=int_1^b1/t dt? I can't understand how the integral having limits from a to ab in Step 1 is equivalent to the integral having limits from 1 to b. I'm a beginner here. Please explain in detail. ln(ab)=int_(1)^(ab)1/x dx = int_(1)^(a)(1)/(x)dx+int_(a)^(ab) 1/x dx =int_(1)^(a) 1/x dx +int_(1)^(b)1/(at) d(at)= int_(1)^(a)1/x dx +int_(1)^(b)1/t dt=ln(a)+ln(b)

$\frac{20b}{{\left(4b^3\right)}^3}$

Which operation could we perform in order to find the number of milliseconds in a year??
${\displaystyle 60\cdot 60\cdot 24\cdot 7\cdot 365}$
${\displaystyle 1000\cdot 60\cdot 60\cdot 24\cdot 365}$
${\displaystyle 24\cdot 60\cdot 100\cdot 7\cdot 52}$
${\displaystyle 1000\cdot 60\cdot 24\cdot 7\cdot 52?}$

Tell about the meaning of Sxx and Sxy in simple linear regression,, especially the meaning of those formulas

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A) No
B) 0
C) Yes
D) 6

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149600000000 is equal to
A)$1.496\times <!--\; \times \; -->{10}^{11}$
B)$1.496\times <!--\; \times \; -->{10}^{10}$
C)$1.496\times <!--\; \times \; -->{10}^{12}$
D)$1.496\times <!--\; \times \; -->{10}^8$

Find the value of$\log 1$ to the base $3$ ?

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write ${\displaystyle \sqrt[5]{{\left(7x\right)}^4}}$ as an equivalent expression using a fractional exponent.

simplify ${\displaystyle \sqrt{125n}}$

What is the square root of ${\displaystyle \frac{144}{169}}$