Is this logarithmic inequality true? Assume we have two complex variables h_i and h_d which satisfy the following relationship 2\ |h_i|^2<= \ |h_d|^2 can we say that \log( 1+ (||h_d| - h_i|^2)/(2)) <= log(1+(1+1/(sqrt(2)))^2 (|h_d|^2)/(2))? Many thanks

Uroskopieulm

Uroskopieulm

Answered question

2022-11-11

Is this logarithmic inequality true?
Assume we have two complex variables h i and h d which satisfy the following relationship
2   | h i | 2   | h d | 2
can we say that
log ( 1 + | | h d | h i | 2 2 ) log ( 1 + ( 1 + 1 2 ) 2 | h d | 2 2 ) ?
Many thanks

Answer & Explanation

Kayleigh Cross

Kayleigh Cross

Beginner2022-11-12Added 19 answers

The logarithm is an increasing function, so your inequality is equivalent to
| | h d | h i | 2 | h d | 2 ( 1 + 1 / 2 ) 2
But
| | h d | h i | | h d | + | h i | | h d | ( 1 + 1 / 2 )
So the inequality follows.

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