How to write Kelvin equation in a different way My question is about the Kelvin equation which is as follows: ln(e/e_s) = (2* sigma)/(n * k * T * r) Keep in mind that the e in ln(e/e_s) is not the constant e.

Ramiro Wise

Ramiro Wise

Answered question

2022-11-22

How to write Kelvin equation in a different way
My question is about the Kelvin equation which is as follows:
ln ( e / e s ) = 2 σ n k T r
Keep in mind that the e in ln ( e / e s ) is not the constant e .
I know that:
e e s = e ( 2 σ n k T r )
I need to show that this is equal to:
e e s = 1 + a r
Where a = 2 σ n k T
How do I go about doing this?

Answer & Explanation

keedriddebadylSE

keedriddebadylSE

Beginner2022-11-23Added 15 answers

You want to show that e a / r = 1 + a / r. But that isn't true. What is true is that
e a / r = 1 + a / r + a 2 2 ! r 2 + a 3 3 ! r 3 +
So if a / r were small, so that a 2 / r 2 and all the following terms on the right were very small, then 1 + a / r would be a good approximation for e a / r .

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