How to evaluate: indefinite integral (1+x)/(1+x^2)dx?

Julia Gallegos

Julia Gallegos

Answered question

2023-03-24

How to evaluate: indefinite integral 1 + x 1 + x 2 d x ?

Answer & Explanation

Mikayla Banks

Mikayla Banks

Beginner2023-03-25Added 7 answers

The integral is
I = ( 1 + x ) d x 1 + x 2 = d x 1 + x 2 + x d x 1 + x 2
The first integral
d x 1 + x 2 = arctan x
And the second integral is
x d x 1 + x 2 = 1 2 2 x d x 1 + x 2
= 1 2 ln ( 1 + x 2 )
Final answer:
I = arctan x + 1 2 ln ( 1 + x 2 ) + C

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?