Find the derivatives. y=\frac{2}{5}\sqrt{\ln^{2}x+x}

Cabiolab

Cabiolab

Answered question

2021-05-03

Find the derivatives.
y=25ln2x+x

Answer & Explanation

toroztatG

toroztatG

Skilled2021-05-04Added 98 answers

The given function is y=25ln2x+x
Obtain the derivative as follows.
dydx=ddx[25ln2x+x]
=2512ln2x+x(2ln(x)x+1)
=15ln2x+x(2ln(x)x+1)
Thus, dydx=15ln2x+x(2ln(x)x+1)

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