sin⁡{(t+2π})=? and cos⁡{(t+2π})=?, so the sine and cosine functions are ? function. The period of each of these is ?.

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Step 1 Let us find sine and cosine value sin⁡{(t+2π})=sin⁡t (sin⁡{(θ+360∘})=sin⁡θ}) cos⁡{(t+2π})=cos⁡t {(cos⁡{(θ+360∘})=cos⁡θ}) sin⁡e and cos⁡ ine are Periodic functions because, A period of the function is the horizontal shift in the cycle sin⁡{(2nπ+θ})=sin⁡θ cos⁡{(2nπ+θ})=cos⁡θforall values ofθandnϵN The basic sine and cosine functions have a period of 2π The function sin⁡x is odd, so its graph is symmetric about the origin The function cos⁡x is even, so its graph is symmetric about y – axis Step 2 Answer sin⁡{(t+2π})=sin⁡t cos⁡{(t+2π})=cos⁡t sin⁡e and cos⁡ ine are periodic function The period of sin⁡e and cos⁡ ine function is 2π

\sin\{(t+2\pi\})=? and \cos\{(t+2\pi\})=?, so the sine and cosine functions are

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