Answer about the graph of the quadratic function y=f(x)=−16x2+160x−256 by analizing the equation algebraically. Then support your answer graphically. What are the x-intercepts?

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Answer about the graph of the quadratic function  y=f(x)=−16x2+160x−256  by analizing the equation algebraically. Then support your answer graphically. What are the x-intercepts?

Annie Gonzalez · Accepted Answer

Step 1  The y-coordinates of all points on the x-axis are 0 and x-intecept is the point where the graph meets the x-axis. Therefore, we can substitute y=0 in the equation to find the x-intercepts.  It is given that  y=−16x2+160x−256  In the above equation, replace y with 0, to get  0=−16x2+160x−256  Divide both sides by -16  0=x2−10x+16  Factorize  0=(x−2)(x−8)  Using the zero product property, we can write  x−2=0 and x−8=0  Solve each linear equation separately  x=2 and x=8  Therefore, th x-intercepts are (2, 0) and (8, 0)

einfachmoipf · Accepted Answer

Step 1  Let y=0, solve for x in the following equation:  −16x2+160x−256=0  Step 2  Since  −16x2+160x−256=−16(x−8)(x−2),  the roots of the equation above are  x1=8 and x2=2  Hence, the x-intercepts are 2 and 8.

Answer about the graph of the quadratic function y=f(x)=-16x^{2}+160x-256 by analizing the

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