For f(x)=(x^{2}+3x-10)^{3}, what is the equation of the line tangent

ennuvolat4gv

ennuvolat4gv

Answered question

2022-02-16

For f(x)=(x2+3x10)3, what is the equation of the line tangent to x=5 and at what point is the tangent line horizontal?

Answer & Explanation

Josef Beil

Josef Beil

Beginner2022-02-17Added 12 answers

We start by differentiating f(x), using the chain rule.
Letting y=u3 and u=x2+3x10. Then dydu=3u2 and (du)/dx=2x+3
Then:
dydx=dydu×dudx
dydx=3u2×2x+3
dydx=(6x+9)(x2+3x10)2
The tangent will be horizontal if its slope is 0. The derivative represents the rate of change of the function at any given point in its domain.
We set the derivative to 0 and solve.
0=(6x+9)(x2+3x10)2
0=6x+9 and 0=x2+3x10
x=96,2,5=32,2,5

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