What is the equation of the line tangent

Raven Gardner

Raven Gardner

Answered question

2022-04-08

What is the equation of the line tangent to f(x)=x2exxex2 at x=0?

Answer & Explanation

Wrastirtyzp9w

Wrastirtyzp9w

Beginner2022-04-09Added 10 answers

Let's rewrite the function as f(x)=x2exxex2
Reminding that the Mac Laurin of ex is 1+x+x22+0(x2),
the one of ex is 1x+x22+0(x2),
and the one of ex2 is 1x2+x42+0(x4)
By replacing them, we get
f(x)=x2(1x+x22+0(x2))x(1x2+x42+0(x4)).
By carrying out the multiplication we get
x+x2+x42x52+0(x4)
In the end f'(0)=-1, i.e. the coefficient of the linear term in the Mac Laurin polynomial for f(x)

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