How do you find the slope of the

Bryant Jacobs

Bryant Jacobs

Answered question

2022-04-11

How do you find the slope of the tangent line of f(x)=32x3 at (-1, 5)?

Answer & Explanation

Kaphefsceasiaf8w9

Kaphefsceasiaf8w9

Beginner2022-04-12Added 9 answers

Explanation:
The slope of the tangent will be the derivative of your function evaluated at
x=-1 (the x coordinate of the tangence point).
So:
f(x)=06x2=6x2
evaluated at x=-1:
f'(-1)=-6
So the slope of the tangent will be -6.

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