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linziboobeary1o8p

linziboobeary1o8p

Answered question

2022-05-11

For any α R determine the limit
lim > δ 0 0 2 1 x δ + x α d x in  [ , + ] .

Answer & Explanation

partyjnopp9wa

partyjnopp9wa

Beginner2022-05-12Added 17 answers

Denote for α R and δ > 0
f α , δ ( x ) = 1 x δ + x α  and  F α ( x ) = 1 x x α .
For x > 0, you have
| f α , δ ( x ) | | F α ( x ) |
and
lim > δ 0 f α , δ ( x ) = F α ( x ) .
As 0 2 | F α ( x ) |   d x is convergent for α < 1, you can apply Dominated Convergent Theorem - DCT in that case and get
lim > δ 0 0 2 1 x δ + x α d x = 0 2 F α ( x )   d x .
So let's now suppose that α 1
You'll easily prove that
1 2 f α , δ ( x )   d x
is bounded by 3 for ( α , δ ) [ 1 , ) × ( 0 , ). This implies the implication
lim > δ 0 0 1 f α , δ ( x )   d x = lim > δ 0 0 2 f α , δ ( x )   d x = .
Now for 0 < x 1 (and α 1 as assumed), we have
0 1 x δ + x f α , δ ( x ) .
We get the desired result as
0 1 1 x δ + x   d x = 1 + ( 1 + δ ) ln ( 1 + 1 δ )
and
lim > δ 0 ( 1 + δ ) ln ( 1 + 1 δ ) = .
Conclusion
lim > δ 0 0 2 1 x δ + x α   d x = { for  α 1 0 2 1 x x α   d x for  α < 1 Conclusion
lim > δ 0 0 2 1 x δ + x α   d x = { for  α 1 0 2 1 x x α   d x for  α < 1

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