Proving that the sequence a_1=4, a_(n+1)=sqrt(a_n+20) onverges and finding its limit

Arectemieryf0

Arectemieryf0

Answered question

2022-07-21

Proving that the sequence a 1 = 4, a n + 1 = a n + 20 converges and finding its limit

Answer & Explanation

uavklarajo

uavklarajo

Beginner2022-07-22Added 17 answers

First let's guess what the limit is (if exists): say a n α, then, by continuity of the operations + and     , we have
α = α + 20 ,    i.e.,    α 2 = α + 20
Its roots are -4 and 5. Since a n > 0 always, only α = 5 can be valid.
Now use induction, with additional hypothesis that a n 5 to prove a n + 1 > a n and still a n + 1 5

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