Evaluate the integral, if it exists. \int (8x^{3}+3x^{2})dx

hionormf

hionormf

Answered question

2021-12-09

Evaluate the integral, if it exists.
(8x3+3x2)dx

Answer & Explanation

censoratojk

censoratojk

Beginner2021-12-10Added 46 answers

Step 1
Given- (8x3+3x2)dx
To evaluate- The above integral.
Formula used- The power rule, xndx=xn+1n+1+C, where C is the constant.
Step 2
Explanation- Rewrite the given integral as
I=(8x3+3x2)dx
Now, using the power rule as xndx=xn+1n+1+C, we get,
I=(8x44+3x33)+C
=(2x4+x3)+C
So, the value of the inteegral is (2x4+x3)+C.
Answer- Hence, the value of the integral I=(8x3+3x2)dxis(2x4+x3)+C, where C is arbitrary constant.
Toni Scott

Toni Scott

Beginner2021-12-11Added 32 answers

(8x3+3x2)dx
Lets

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