interdicoxd

2021-12-31

Evaluate the integral.

${\int}_{-8}^{4}(-2x+8)dx$

scomparve5j

Beginner2022-01-01Added 38 answers

Step 1

Given definite integral is:

${\int}_{-8}^{4}(-2x+8)dx$

We have to evaluate the above definite integral.

Step 2

Then we get,

${\int}_{-8}^{4}(-2x+8)dx$

$={\int}_{-8}^{4}(-2x)dx+{\int}_{-8}^{4}8dx$

$=-2{\int}_{-8}^{4}xdx+8{\int}_{-8}^{4}dx$

$=-2{\left[\frac{{x}^{2}}{2}\right]}_{-8}^{4}+8{\left[x\right]}_{-8}^{4}$

$=-2\times \frac{1}{2}\times [{4}^{2}-{(-8)}^{2}]+8[4-(-8)]$

=-(16-64)+8(4+8)

=-16+64+96

=144

Hence the answer.

Given definite integral is:

We have to evaluate the above definite integral.

Step 2

Then we get,

=-(16-64)+8(4+8)

=-16+64+96

=144

Hence the answer.

kaluitagf

Beginner2022-01-02Added 38 answers

Use properties

Evaluate

Return the limits

Calculate the expression

Answer:

144

Vasquez

Expert2022-01-07Added 669 answers

Step 1

Given

Step 2

Solution:

Let's calculate a definite integral:

F(4)=16

F(-8)=-128

I=16-(-128)=144

NSK

Answer:

144

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