What is the arclength of f ( x ) = <msqrt> 4 &#x2212;<!-- − --> x

robinmarian9nhn8

robinmarian9nhn8

Answered question

2022-05-14

What is the arclength of f ( x ) = 4 x 2 in the interval [-2,2]?

Answer & Explanation

necrologo9yh43

necrologo9yh43

Beginner2022-05-15Added 23 answers

This is a semi circle of radius 2. We simply find the perimeter of the full circle of radius 2 and divide it by 2 to get our arc length.
P = 2 ( 2 ) π = 4 π
P 2 = 4 π 2 = 2 π
Therefore the arc length is 2 π units.

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