Integration of trigonometric function &#x222B;<!-- ∫ --> sin &#x2061;<!-

Akira Huang

Akira Huang

Answered question

2022-05-21

Integration of trigonometric function sin ( 2 x ) sin ( x ) cos ( x ) d x

Answer & Explanation

pelankp

pelankp

Beginner2022-05-22Added 8 answers

HINT:
sin ( 2 x ) sin ( x ) cos ( x )   d x =
Use sin ( 2 x ) = 2 sin ( x ) cos ( x )
2 sin ( x ) cos ( x ) sin ( x ) cos ( x )   d x =
Sustitute u = tan ( x 2 ) and d u = x sec 2 ( x 2 ) 2   d x:
8 u ( u 2 1 ) ( u 2 + 1 ) 2 ( u 2 + 2 u 1 )   d u
Landyn Jimenez

Landyn Jimenez

Beginner2022-05-23Added 3 answers

Let u = x π 4 , then
sin ( 2 x ) sin ( x ) cos ( x ) d x = sin ( 2 u + π 2 ) 2 sin ( u ) d u = 1 2 cos ( 2 u ) sin ( u ) d u = 1 2 1 2 sin 2 ( u ) sin ( u ) d u = 1 2 sin ( u ) 1 cos 2 ( u ) d u 2 sin ( u ) d u = 2 cos ( u ) 1 2 2 ( 1 1 cos ( u ) + 1 1 + cos ( u ) ) d cos ( u ) = 2 cos ( u ) + 1 2 2 log ( 1 cos ( u ) 1 + cos ( u ) ) + C = 2 cos ( u ) + 1 2 log ( tan ( u / 2 ) ) + C

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