Examine the uniform convergence of <munderover> &#x2211;<!-- ∑ --> <mrow class="MJX-TeXAt

hughy46u

hughy46u

Answered question

2022-05-24

Examine the uniform convergence of n = 1 x ( 1 + n x ) ( 1 + ( n + 1 ) x )

Answer & Explanation

Conor Frederick

Conor Frederick

Beginner2022-05-25Added 7 answers

Note that
x ( 1 + n x ) ( 1 + ( n + 1 ) x ) = 1 1 + n x 1 1 + ( n + 1 ) x
and that therefore
S m ( x ) = 1 1 + x 1 1 + ( m + 1 ) x .
So, if
S ( x ) = m = 1 x ( 1 + n x ) ( 1 + ( n + 1 ) x ) ,
then
S ( x ) = 1 1 + x lim n 1 1 + n x = { 1 1 + x  if  x > 0 0  if  x = 0.
The convergence is not uniform on [ 0 , ), since
( m N ) : S m ( 1 m + 1 ) = m + 1 m + 2 1 2
and
lim m m + 1 m + 2 1 2 = 1 2 0 = S ( 0 ) .
Or you can say that if the convergence was uniform, then S would be continuous, but that's not the case.
But the convergense is uniform on [ a , ), if a>0

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